WebAny point on the x-axis has the coordinates (a, 0). The distance between (0, -3) and (0, 3) is 6. Hence, the distance between (a, 0) and (0, 3) should also be 6. 62 = (a - 0)2 + (0 - 3)2 36 = a2 + 9 a2 = 27 Solution 49 Solution 50 Using the distance formula, AB= AC= BC= PQ= PR= QR= Now, ΔABC ~ ΔPQR by the SSS test. Solution 51 Solution 52 WebCoordinate Geometry Introduction: NCERT Exercise 7.1 Solutions Class 10 Maths (New Session 2024-23) By Rahul Sir Complete CBSE Course All Chapters Available Coordinate Geometry -...
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